Quadratic functions are polynomials of degree 2 and can be expressed in the standard form: f(x)=ax2+bx+c
where a, b, and c are constants, and a=0. The graph of a quadratic function is a parabola.
Key Properties:
Vertex: The vertex of the parabola is the point where it changes direction. It can be found using the formula: x=−2ab
The corresponding y-value can be found by substituting this x back into the function.
Axis of Symmetry: The vertical line that passes through the vertex is called the axis of symmetry, given by the equation: x=−2ab
Y-intercept: The point where the graph intersects the y-axis is given by the value c, or (0,c).
Roots (X-intercepts): The points where the graph intersects the x-axis can be found using the quadratic formula: x=2a−b±b2−4ac
The expression b2−4ac is known as the discriminant and determines the nature of the roots.
Example:
Find the vertex and roots of the quadratic function f(x)=2x2−4x+1.
Identify coefficients: a=2, b=−4, c=1
Find the vertex: x=−2⋅2−4=44=1
Substitute x=1 into f(x) to find y: f(1)=2(1)2−4(1)+1=2−4+1=−1
So, the vertex is (1,−1).
Find the roots using the quadratic formula: x=2(2)−(−4)±(−4)2−4(2)(1) =44±16−8 =44±8 =44±22 =1±22
Thus, the roots are 1+22 and 1−22.
Key Questions:
What is the vertex of the quadratic f(x)=3x2+6x+2?
How do you determine the number of roots for the function f(x)=x2−4?
What is the axis of symmetry for the parabola represented by f(x)=−x2+2x+3?
Keywords: quadratic function, vertex, axis of symmetry, roots, discriminant
Next: Lesson 2
Lesson 2
Find the y-intercept of the quadratic function f(x)=5x2−3x+7.
Keywords:
Quadratic function
Vertex
Axis of symmetry
Roots
Discriminant
Keywords: quadratic function, vertex, axis of symmetry, roots, discriminant